Print Matrix in a circular path (Interview question)

Hi friends,

This is one of the interview questions I faced recently and thought I would share it.

Question:
Given a matrix print all its value in a circular fashion like shown in the image below.

Solution:
To attack this problem we definitely want to have a left-right, top-bottom, right-left and bottom-top spans. For attaining this, we obviously want to have 4 loops. The C++ code is given below.

//============================================================================
// Name        : circular_matrix_read.cpp
// Author      : c++
// Description : output given matrix elements circularly
//============================================================================

#include <iostream>
using namespace std;

#define HEIGHT 6
#define WIDTH  3

int main()
{
 //int array[HEIGHT][WIDTH] = {{1,2,3,4,5},{16,17,18,19,6},{15,24,25,20,7},{14,23,22,21,8},{13,12,11,10,9}};
 //int array[HEIGHT][WIDTH] = {{1,2,3,4,5,6},{14,15,16,17,18,7},{13,12,11,10,9,8}};
 int array[HEIGHT][WIDTH] = {{1,2,3},{14,15,4},{13,16,5},{12,17,6},{11,18,7},{10,9,8}};
 int maxh = HEIGHT-1, maxw = WIDTH-1;
 int minh = 0, minw = 0;
 while(1)
 {
  if(minh > maxh || minw > maxw)
   break;

  //top-left to top-right
  for(int i=minh,j=minw;j<=maxw;j++)
   cout << array[i][j] << endl;
  minh++;

  if(minh > maxh || minw > maxw)
   break;

  //top-right to bottom-right
  for(int i=minh,j=maxw;i<=maxh;i++)
   cout << array[i][j] << endl;
  maxw--;

  if(minh > maxh || minw > maxw)
   break;

  //bottom-right to bottom-left
  for(int i=maxh,j=maxw;j>=minw;j--)
   cout << array[i][j] << endl;
  maxh--;

  if(minh > maxh || minw > maxw)
   break;

  //bottom-left to top-left
  for(int i=maxh,j=minw;i>=minh;i--)
   cout << array[i][j] << endl;
  minw++;
 }
 return 0;
}
//1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

Cheers!
Bragaadeesh.