You are given the following information, but you may prefer to do some research for yourself.
- 1 Jan 1900 was a Monday.
- Thirty days has September,
April, June and November.
All the rest have thirty-one,
Saving February alone,
Which has twenty-eight, rain or shine.
And on leap years, twenty-nine. - A leap year occurs on any year evenly divisible by 4, but not on a century unless it is divisible by 400.
Solution (in Ruby)
This particular solution does not involve any hard calculations, just run through the dates starting from the first sunday step by 7 days and check if the sunday lies on the first day of the month.
require 'date' d1, d2, total_sundays = [Date::civil(1901, 1, 1), Date::civil(2000, 12, 31), 0] d1 +=1 while (d1.wday != 0) d1.step(d2, 7){|date| total_sundays+=1 if date.day == 1} puts "Total number of Sundays : #{total_sundays}"
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